b^2+20b+64=0

Solution for b^2+20b+64=0 equation:

Simplifying
b2 + 20b + 64 = 0

Reorder the terms:
64 + 20b + b2 = 0

Solving
64 + 20b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(16 + b)(4 + b) = 0

Subproblem 1
Set the factor '(16 + b)' equal to zero and attempt to solve:

Simplifying
16 + b = 0

Solving
16 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + b = 0 + -16

Combine like terms: 16 + -16 = 0
0 + b = 0 + -16
b = 0 + -16

Combine like terms: 0 + -16 = -16
b = -16

Simplifying
b = -16
Subproblem 2
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Solution
b = {-16, -4}